Obtain the equation of the normal to the curve y = x/[(√x) -2] at the point on the curve where x = 1.?
Obtain the equation of the normal to the curve y = x/[(√x) -2] at the point on the curve where x = 1.
I don't know what to do with the √x, any help is appreciated!
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At x = 1, the slope of y is -3/2:
http://www.flickr.com/photos/dwread/8683973552/
The slope of the normal at (1, -1) is 2/3.
Point-slope equation of the normal:
y + 1 = (2/3)(x - 1)
Slope-intercept equation
y = (2/3)x - 5/3
http://www.flickr.com/photos/dwread/8684009732/in/...