No triângulo a seguir, determine a medida x e sen α.?
o link do exercicio ae !!
http://cursocaes.com.br/pdfs/1417262818.pdf
ta na pagina 3 exercicio 3
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o link do exercicio ae !!
http://cursocaes.com.br/pdfs/1417262818.pdf
ta na pagina 3 exercicio 3
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Answers & Comments
Ola joao
tg(75) = 2 + √3
tg(75) = 10/x
x = 10/tg(75) = 10/(2 + √3)
x = 10*(2 - √3)/(2 - √3)*(2 + √3)
x = 20 - 10√3
y = x + 2*(10 + √3)
y = 20 - 10√3 + 20 + 2√3
y = 40 - 8√3
hipotenusa
h² = 10² + (40 - 8√3)²
h² = 1892 - 640√3
h = 28
sen(α) = 10/h = 10/28 = 5/14
pronto