Fiz os cálculos e dava -2sen4a.cos3a, mas no gabarito consta 2sen4a.cos3a. Qual o certo?
Ola Joao
sen(a) + sen(b) = 2*sen[(a+b)/2]*cos[(a-b)/2]
sen(7a) + sen(a) = 2*sen[(7a+a)/2]*cos[(7a-a)/2]
= 2*sen(4a)*cos(3a)
pronto
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Answers & Comments
Ola Joao
sen(a) + sen(b) = 2*sen[(a+b)/2]*cos[(a-b)/2]
sen(7a) + sen(a) = 2*sen[(7a+a)/2]*cos[(7a-a)/2]
= 2*sen(4a)*cos(3a)
pronto