Verified answer

NH4Cl is a salt of weak base NH3 and strong acid HCl ...and pH of such salt solution is given by :-

pH = 1/2 [ pKw -pKb - log c ]

where pKw = -log 10^-14 = 14

pKb = -log Kb = -log (1.8 X 10^-5) = 4.745

log c = log 0.087 = -1.06

pH = 1/2 [ 14 - 4.745 - (-1.06) ] = 1/2 [ 14 - 4.745 + 1.06 ] = 10.315/2 = 5.158

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NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts as a weak acid. What is the pH of a solution t?

NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts as a weak acid. What is the pH of a solution that is 0.087 M in NH4C