In a circuit where wires carry current, the wires would have the least resistance if they were...
Update:Answers that it gives me are
- as long as possible
- as short as possible
- as thin as possible
- none
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Rosie, resistance = resistivity X length of the wire. Resistivity is a bit like density but in this case it's resistance over distance. So naturally resistance R = rho L; where rho is the resistivity in ohms per meter for example.
So since rho is a fixed value we see that the resistance of that wire varies directly as R = rho L with the length of the wire L. The closer L gets to zero length the closer R gets to zero also. As short as possible. ANS.
The thinness is a bit more complex. Think of a wire to be like a water pipe. Which pipe, the large one or the small one, would carry the most water? The large one naturally. Same sort of deal with a wire. The bigger (thicker) wire will carry the most free electrons so there is less resistance to them flowing.
As short as possible like plumbing but that analogy is still lacking.