N2 + 3H2 → 2NH3 ... Chemistry Moles Problems?
a. how many grams of h2 are needed to react completely with 50.0 grams of N2?
b. How many grams of NH3 would be produced?
c. How mnay moles of N2 is this?
d. How many moecules of NH3 were produced?
e. How many atoms of H2 reacted?
Please help! A bit struggling... :(
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a.
(50.0 g N2) / (28.01344 g N2/mol) x (3 mol H2 / 1 mol N2) x (2.015894 g H2/mol) =
10.8 g H2
b.
(50.0 g N2) / (28.01344 g N2/mol) x (2 mol NH3 / 1 mol N2) x (17.03056 g NH3/mol) =
60.8 g NH3
c.
(50.0 g N2) / (28.01344 g N2/mol) = 1.78 mol N2
d.
(50.0 g N2) / (28.01344 g N2/mol) x (2 mol NH3 / 1 mol N2) x
(6.022 x 10^23 molecules/mol) = 2.15 x 10^24 molecules NH3
e. H2 doesn't come in atoms. Supposing the question to be: "How many atoms of hydrogen reacted?":
(50.0 g N2) / (28.01344 g N2/mol) x (3 mol H2 / 1 mol N2) x
(6.022 x 10^23 molecules/mol) x (2 atoms/molecule) = 6.45 x 10^24 atoms H