cosθ = -12/13
sin²θ = 1-cos²θ = 25/169
Since θ is in quadrant III, sinθ = -√(25/269) = -5/13
tanθ = sinθ/cosθ = 5/12
secθ = 1/cosθ = -13/12
Sin ϴ=-5/13
Tan ϴ=5/12
and sec ϴ=-13/12
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Verified answer
cosθ = -12/13
sin²θ = 1-cos²θ = 25/169
Since θ is in quadrant III, sinθ = -√(25/269) = -5/13
tanθ = sinθ/cosθ = 5/12
secθ = 1/cosθ = -13/12
Sin ϴ=-5/13
Tan ϴ=5/12
and sec ϴ=-13/12