matematica essa é so pra quem é pica na xereca !!!?
resolva √ [ (2(a * b )^1/2 ) / ( b - a ) ] ² + 1 tem que dar a + b / a - b
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resolva √ [ (2(a * b )^1/2 ) / ( b - a ) ] ² + 1 tem que dar a + b / a - b
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√ [ (2(a * b )^1/2 ) / ( b - a ) ] ² + 1 =
Eliminado o sinal de √ (raiz) temos
[ (2(a * b )^1/2 ) / ( b - a ) ] + 1 =
mmc = (b - a )
[ (2(a * b )^1/2 ) + (b-a)] / ( b - a ) =