Veja:
∫(cotgx)dx=
∫cos(x)dx/sen(x)=
u=sen(x)
du=cos(x)dx
∫du/u=
ln(u)+c=
ln[sen(x)] +c
log sen (x) + constante
há sites que fazem isso:
http://manthanos.blogspot.com/2011/03/o-site-que-c...
:D
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Verified answer
Veja:
∫(cotgx)dx=
∫cos(x)dx/sen(x)=
u=sen(x)
du=cos(x)dx
∫cos(x)dx/sen(x)=
∫du/u=
ln(u)+c=
ln[sen(x)] +c
log sen (x) + constante
há sites que fazem isso:
http://manthanos.blogspot.com/2011/03/o-site-que-c...
:D