Na equação: X² - nx + 36 = 0, determine n, de modo que:
A. uma das raízes seja igual a 4.
B. as raízes sejam iguais
C. uma das raízes seja 4/3.
x² - nx + 36 = 0
A)
4² - 4n + 36 = 0
4n = 16 + 36 = 52
n = 52/4 = 13
B)
r² = 36
r = 6
2r = 12
n = 12
C)
(4/3)² - n*(4/3) + 36 = 0
16/9 - n*(4/3) + 36 = 0
(4/3)*n = (16 + 9*36)/9 = 340/9
n = (340/9)/(4/3) = (340/9)*(3/4) = 1020/36 = 255/9
pronto
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Verified answer
x² - nx + 36 = 0
A)
4² - 4n + 36 = 0
4n = 16 + 36 = 52
n = 52/4 = 13
B)
r² = 36
r = 6
2r = 12
n = 12
C)
(4/3)² - n*(4/3) + 36 = 0
16/9 - n*(4/3) + 36 = 0
(4/3)*n = (16 + 9*36)/9 = 340/9
n = (340/9)/(4/3) = (340/9)*(3/4) = 1020/36 = 255/9
pronto