Ok...if you have two limits that are like what you have above then you can use L'hopitals rule on each.
You must find derivatives of both numerators and denominators and see what the difference equals in the limit. If this is not sufficient then you have to take derivatives again...and see what happens.
It is meaningless by itself but is â/â in a limit (as long as that is a times and not a minus. If it is a minus, you have to do the subtraction before you can determine the form)
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It is an indetermination, nobody knows.
Three values we can obtain from ∞/∞
Zero (0) since we divide by infinity.
One (1) since we divide the same number.
Infinity (∞) since we have infinity in the numerator.
However, you must know that in order to use L'Hôpital
Rule the indetermination yielded from the limit must be
0/0 or ∞/∞.
:)
Ok...if you have two limits that are like what you have above then you can use L'hopitals rule on each.
You must find derivatives of both numerators and denominators and see what the difference equals in the limit. If this is not sufficient then you have to take derivatives again...and see what happens.
Have fun.
It is meaningless by itself but is â/â in a limit (as long as that is a times and not a minus. If it is a minus, you have to do the subtraction before you can determine the form)
â/â - is indeterminate