Just plug in h=0.1, then 0.01, then 0.001, etc. and the result will be 0.05, 0.005, 0.0005, etc. (Try it...don't take my word. Make sure your calculator is in radians!)
All but the first are 0.0 rounded to 1 decimal place, so 0.0 is the answer I'd write.
@iggy rocko: Uh, you can't use L'Hopital on this limit. This and the limit of (sin x)/x are needed to establish the derviatve of the cosine...so taking the derivative to find this limit is circular reasoning.
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SO DO IT !....{ 0 }
Just plug in h=0.1, then 0.01, then 0.001, etc. and the result will be 0.05, 0.005, 0.0005, etc. (Try it...don't take my word. Make sure your calculator is in radians!)
All but the first are 0.0 rounded to 1 decimal place, so 0.0 is the answer I'd write.
@iggy rocko: Uh, you can't use L'Hopital on this limit. This and the limit of (sin x)/x are needed to establish the derviatve of the cosine...so taking the derivative to find this limit is circular reasoning.
lim cosh - 1/h = -â
h-> 0
cos0 = 1 and 1/h approaches â
Edit: Okay, I'll delete it.