Let f(x) = (from x^2 + 1 to x^3 + x)∫ sin(1+t^2)dt. Find f'(x)?
Let f(x) = (from x^2 + 1 to x^3 + x)∫ sin(1+t^2)dt. Find f'(x)?
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Let f(x) = (from x^2 + 1 to x^3 + x)∫ sin(1+t^2)dt. Find f'(x)?
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Let g(t) = ∫ sin(1+t^2)dt
Then g '(t) = sin(1+t^2)
f(x) = g(x^3 + x) - g(x^2 + 1)
f '(x) = g '(x^3 + x) * d/dx[x^3+x] - g '(x^2+1) * d/dx[x^2+1]
= sin(1+(x^3+x)^2) * (3x^2+1) - sin(1+(x^2+1)^2) * (2x)