b is a base of log , b > 1 .
Given inequality is logb(n+c) ≦ logb(n) + d and c ≧ 0 .
We want to prove there is a non-negative value d such that given inequality is satisfied for n ≧ 1 .
logb(n+c) = logb[n(1 + c/n)] = logb(n) + logb(1 + c/n) .
Therefore given inequality becomes
logb(n) + logb(1 + c/n) ≦ logb(n) + d
logb(1 + c/n) ≦ d
So if d satisfies logb(1 + c/n) ≦ d then given inequality is satisfied .
logb(x) is an increasing function and 1 + c/n ≦ 1 + c for n ≧ 1 , so logb(1 + c/n) ≦ logb(1 + c) .
Therefore , if d satisfies log(1 + c) ≦ d then given inequality is satisfied for n ≧ 1 .
Such d is always exist .
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b is a base of log , b > 1 .
Given inequality is logb(n+c) ≦ logb(n) + d and c ≧ 0 .
We want to prove there is a non-negative value d such that given inequality is satisfied for n ≧ 1 .
logb(n+c) = logb[n(1 + c/n)] = logb(n) + logb(1 + c/n) .
Therefore given inequality becomes
logb(n) + logb(1 + c/n) ≦ logb(n) + d
logb(1 + c/n) ≦ d
So if d satisfies logb(1 + c/n) ≦ d then given inequality is satisfied .
logb(x) is an increasing function and 1 + c/n ≦ 1 + c for n ≧ 1 , so logb(1 + c/n) ≦ logb(1 + c) .
Therefore , if d satisfies log(1 + c) ≦ d then given inequality is satisfied for n ≧ 1 .
Such d is always exist .