(45% de 1.1783 g/ml) / (98.0791 g H2SO4/mol) = 0.0054062 mol/ml =
5.4062 mol/L = 5.4 M H2SO4
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(45% de 1.1783 g/ml) / (98.0791 g H2SO4/mol) = 0.0054062 mol/ml =
5.4062 mol/L = 5.4 M H2SO4
[No entiendo "(24)".]