Well first we use the identity 1 + (cot x)^2 = (cosec x)^2
so our integral becomes:
integral from pi/6 to pi/2 of cosec x dx
which is equal to [cosec x cot x] between pi/6 and pi/2, which is equal to (1)(0) - (2)(rt(3)) = -2rt(3)
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
Well first we use the identity 1 + (cot x)^2 = (cosec x)^2
so our integral becomes:
integral from pi/6 to pi/2 of cosec x dx
which is equal to [cosec x cot x] between pi/6 and pi/2, which is equal to (1)(0) - (2)(rt(3)) = -2rt(3)