integrate ⌡(4x^5 - 9x +2)
this is to measure the area of a curve
= (4/6)x^6 - (9/2)x^2 + 2x + c
= (2/3)x^6 - (9/2)x^2 + 2x + c
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= (4/6)x^6 - (9/2)x^2 + 2x + c
= (2/3)x^6 - (9/2)x^2 + 2x + c