(4,0 mol HCl) x (36,4611 g HCl/mol) = 145,8444 g HCl
(145,8444 g) / (145,8444 g + (10 x 10^3 g)) = 0,0143748 = 1,4% HCl in massa
massa acido = moli * peso molecolare
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(4,0 mol HCl) x (36,4611 g HCl/mol) = 145,8444 g HCl
(145,8444 g) / (145,8444 g + (10 x 10^3 g)) = 0,0143748 = 1,4% HCl in massa
massa acido = moli * peso molecolare