the uncertainty of the momentum in this direction? (Useful constant: h-bar = 1.05×10-34 Js.). Created by Alexandra. science-mathematics-en - physics-en

If the x position of a particle is measured with an uncertainty of 1.00×10-10 m, then what is..?

May 2021 2 34 Report

If the x position of a particle is measured with an uncertainty of 1.00×10-10 m, then what is..?

the uncertainty of the momentum in this direction? (Useful constant: h-bar = 1.05×10-34 Js.)

Uncertainty principle

dxdp is greater than or equal to h-bar/2pi

dx = 1.00*10^-10 m

dp = 1.05*10^-34/(2pi*1.00*10^-10) = 1.05*10^-34/6.283*10^-10

dp = 0.167*10^-24 = 1.67*10^-25 Jsm^-1

PS Jessica

it's not 6.597E-34/4pi it's 6.597E-34/4pi^2. You need to divide your answer by pi

Uncertainty principle

dxdp is greater than or equal to h/4pi

h-bar=h/2pi

Use h-bar to solve for h:

1.05E-34=h/2pi

h=1.05E-34(2pi)=6.597E-34 J*s

Solve first equation for dp and plug in h:

dp=(6.597E-34/4pi)/(1E-10)=5.25E-25 J*s*m

Units can also be kg*m/s, which is what my homework made it.