Hmm I think your missing D = distance from the equation. I cant see how you can solve an equation that requires 2 out of 3 unknowns when we only know 1 unknown ( time).
If you have D; then its just velocity = distance / time
In a given volume of time, if the instant velocities at any on the spot are equivalent to the popular velocity in that quantity of time, then the physique is declared to go with consistent velocity for the duration of that quantity of time.
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what kind of a question is this?
Hmm I think your missing D = distance from the equation. I cant see how you can solve an equation that requires 2 out of 3 unknowns when we only know 1 unknown ( time).
If you have D; then its just velocity = distance / time
average time = 3.5 + 0 / 2 = 3.5/2 = 1.75
V = D/1.75
In a given volume of time, if the instant velocities at any on the spot are equivalent to the popular velocity in that quantity of time, then the physique is declared to go with consistent velocity for the duration of that quantity of time.