If tan(t) = 3 and π ≤ t ≤ 3pi/2, what is cos(t)?
Update:
If you could provide the property/solution I would be thankful!
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If you could provide the property/solution I would be thankful!
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sec(t)^2 - tan(t)^2 = 1
sec(t) = 1 / cos(t)
sec(t)^2 - tan(t)^2 = 1
sec(t)^2 - 9 = 1
sec(t)^2 = 10
cos(t)^2 = 1/10
cos(t) = +/- sqrt(1/10)
cos(t) = +/- 1 / sqrt(10)
cos(t) = +/- sqrt(10) / 10
We're in Q3, so cos(t) < 0
cos(t) = -sqrt(10) / 10