If f′(x)=3x and f(2)=−1, approximate f(2.1) to one decimal place?
f′(x)= (f(x+h) - f(x))/h
f′(2)= (f(2.1) -f(2))/0.1
6=(x - -1)/0.1
0.6=x+1
then x = -0.4 = f(2.1)
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f′(x)= (f(x+h) - f(x))/h
f′(2)= (f(2.1) -f(2))/0.1
6=(x - -1)/0.1
0.6=x+1
then x = -0.4 = f(2.1)