if f '(x) = - 3x - 2 the f (x) = (-3/2) x^2 - 3x + C
f( -4) = - 13
f (- 4) = (- 3/2) (-4^2) - 2 (- 4) + C
f( - 4) = (- 3/2) (16) + 8 + C
f ( - 4) = - 24 + 8 + 6
f( -4)= - 16 + C = - 13
C = 3
f (x) = (- 3/2)x^2 - 2x + 3
the same as the above answer ^_^
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if f '(x) = - 3x - 2 the f (x) = (-3/2) x^2 - 3x + C
f( -4) = - 13
f (- 4) = (- 3/2) (-4^2) - 2 (- 4) + C
f( - 4) = (- 3/2) (16) + 8 + C
f ( - 4) = - 24 + 8 + 6
f( -4)= - 16 + C = - 13
C = 3
f (x) = (- 3/2)x^2 - 2x + 3
the same as the above answer ^_^