Work from the outside in:
d/dx[f(1/x)]=x²
f(1/x) = 1/3 x^3
f(x) = 1/3 x^-3
f'(x) = -x^-4
f'(1/x) = -x^4
The answer is -x^4
You can also do this by noting that with the Chain Rule:
d/dx[f(1/x)] = d/dx(1/x) * f'(1/x) = -1/x^2 * f'(1/x) = x^2
Therefore f'(1/x) = -x^4
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Verified answer
Work from the outside in:
d/dx[f(1/x)]=x²
f(1/x) = 1/3 x^3
f(x) = 1/3 x^-3
f'(x) = -x^-4
f'(1/x) = -x^4
The answer is -x^4
You can also do this by noting that with the Chain Rule:
d/dx[f(1/x)] = d/dx(1/x) * f'(1/x) = -1/x^2 * f'(1/x) = x^2
Therefore f'(1/x) = -x^4