if cos Ɵ = m/n
then, the adjacent side is: m
the hypotenuse is: n
so, the opposite side is: ? (use the Pythagorean theorem...
did you get √(n^2 - m^2) ?
tan Ɵ = [√(n^2 - m^2)]/m
qed
If cos Æ = m/n, then sin Æ = â(n^2 - m^2)/n.
So tan Æ = â(n^2 - m^2)/m
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Verified answer
if cos Ɵ = m/n
then, the adjacent side is: m
the hypotenuse is: n
so, the opposite side is: ? (use the Pythagorean theorem...
did you get √(n^2 - m^2) ?
tan Ɵ = [√(n^2 - m^2)]/m
qed
If cos Æ = m/n, then sin Æ = â(n^2 - m^2)/n.
So tan Æ = â(n^2 - m^2)/m