cosØ = 3/5 therefore if you draw a triangle with that information you will have the hypotenuse = 5 the adjacent side equal to 3 and the angle Ø between the two lines.
After drawing this right angled triangle you will see that by using Pythagorus's thereom you can find the third side
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For this one you have to draw a triangle!
cosØ = 3/5 therefore if you draw a triangle with that information you will have the hypotenuse = 5 the adjacent side equal to 3 and the angle Ø between the two lines.
After drawing this right angled triangle you will see that by using Pythagorus's thereom you can find the third side
25 - 9 = c^2
16 = c^2
c = 4
Therefore you have the opposite side = 4
then using trig you know that
sinØ = 4/5.
step 2
sin2Ø expands to 2sinØcosØ
but we know sinØ = 4/5 and cosØ = 3/5
therefore the answer is 2 * 4/5 * 3/5
= 24/5