If an air sample contains 48 ppm CO and 2 × 10^6 molecules of air, how many CO molecules are present?
If an air sample contains 48 ppm CO and 2 ×
10^6 molecules of air, how many CO molecules
are present?
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ppm = (part/whole) x 10^6 ppm
so if n is number molecules of CO
48 ppm = (n/2x10^6) x 10^6 ppm
solve for n = 2 x 48 = 96 molcules CO
(48x10^-6)(2 x 10^6)