If 2x^2+4x+xy=3 and y(3)=−9 , find y prime (3) by implicit differentiation.
2x^2 + 4x + xy = 3
4x * dx + 4dx + xdy + ydx = 0
dx * (4x + 4 + y) = -x * dy
dy / dx = -(4x + 4 + y) / x
x = 3
y = -9
dy/dx = -(4 * 3 + 4 - 9) / 3
dy/dx = -(7) / 3
Diferentiate each and each term, pondering the produt interior the 1st 2 words. 2xy + x^2(dy/dx) -y^3 -x3y^2dy/dx = 0 - 6x^2 now placed dy/dx in information: (dy/dx)(x^2 -3xy^2) = -6x^2 - 2xy + y^3 Then: dy/dx = (-6x^2 -2xy + y^3)/( x^2 -3xy^2) ok
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2x^2 + 4x + xy = 3
4x * dx + 4dx + xdy + ydx = 0
dx * (4x + 4 + y) = -x * dy
dy / dx = -(4x + 4 + y) / x
x = 3
y = -9
dy/dx = -(4 * 3 + 4 - 9) / 3
dy/dx = -(7) / 3
Diferentiate each and each term, pondering the produt interior the 1st 2 words. 2xy + x^2(dy/dx) -y^3 -x3y^2dy/dx = 0 - 6x^2 now placed dy/dx in information: (dy/dx)(x^2 -3xy^2) = -6x^2 - 2xy + y^3 Then: dy/dx = (-6x^2 -2xy + y^3)/( x^2 -3xy^2) ok