Verified answer

Reaction: S + O2 ---> SO2

(2.75 kg)(1 kg-mole / 32.065 kg) = 0.08576 kg-moles

And since SO2 is produced in a 1:1 ratio

(0.08576 kg-moles)(1000 g/kg) = 85.76 moles SO2

Using ideal gas law: PV = nRT

Substituting: (1.01)V = (85.76)(82.05746 atm*cm^3/ (mol * K))(295.4 K)

Solve for V

V = 2.06 x 10^6 mL