Verified answer

This is x³ + x² - 12 =0 and integer solutions are factors of 12 so could be

1,2,3,4,6,12 (+ or -). Trying each you see that x=2 is a root so (x-2) is a factor

and dividing x³ + x² - 12 by (x-2) gives x² +3x+6 so the other roots are found from]

x² +3x+6 =0 which has complex roots x = (-3-sqrt(-15))/2 = -(3+isqrt(15))/2

and x=- (3-isqrt(15))/2.

i is the such that i^2=-1.

There are complicated ways to solve cubic equations - try Yahoo Answers looking

for the exact solutions of a cubic equation.

12 = 2³ + 2². So:

x³ + x² = 2³ + 2²

I know of no other way.

X^3*X^2=X*X*X*X*X. so X^5 is 12. Then you can raise each side to the one fifth power, meaning the fifth root of 12. Put this into a calculator and you get 2.

x³ + x² = 12

x³ + x² - 12 = 0

(x-2)(x² +3x+6) = 0

(x-2)((x + (3/2)^2 - (i√(15)/2)^2)=0

(x-2)(x + (3/2) - i√(15)/2)(x + (3/2) + i√(15)/2)=0

Zeros are 2 and two complex conjugated - (3/2) ± i√(15)/2

x³ + x² = 12------>

(x³ -8)+ (x² -4)=0------>

(x-2)(x² +2x+4) +(x-2)(x+2)=0------>

(x-2)(x² +2x+4+x+2)=0------>

(x-2)(x² +3x+6)=0------>x=2