How to solve this (no integrals) d/dx [from 3 to x²]∫ cos(t) / ³√(t⁴+2)?
I asked this twice earlier, but no answers... and I'm still lost.
Any help/answers/helpful links would be appreciated, thanks..
d/dx [from 3 to x²]∫ cos(t) / ³√(t⁴+2)
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There's a mistake in Rob's answer. You have to use the chain rule, so that the right answer is
f(g(x)) g'(x) = cos(x^2)/((x^8 + 2)^(1/3)) 2x
need to use Leibnitz's form of the Fundamental Theorem
d / dx { int over [ a(x), b(x) ] of F(t) ft = F(b(x)) { db / dx } - F(a(x)) {da / dx }
( cos x² / [ x^8 + 2]^(1/3) ) { 2x }