2/(x + 1) + 3/(x - 1) = 5/(x² - 1)
(2x - 2 + 3x + 3)/(x² - 1) = 5/(x² - 1)
5x + 1 = 5
5x = 4
x = 4/5
Answer: x = 4/5
Proof:
2/(4/5 + 1) + 3/(4/5 - 1) = 5/([4/5]² - 1)
2/(4/5 + 5/5) + 3/(4/5 - 5/5) = 5/(16/25 - 25/25)
2/(9/5) + 3/(- 1/5) = 5/(- 9/25)
2(5/9) + 3(- 5) = 5(- 25/9)
10/9 - 15 = - 125/9
10/9 - 135/9 = - 125/9
- 125/9 = - 125/9
2/(x+1)+3/(x-1)=5/(x^2-1)
now solving you will get
2(x-1)+3(x+1)/(x^2-1)=5/(x^2-1)
cancelling out we get
5x-4=0
x=4/5
2/(x+1) + 3/(x-1) = 5/(x^2 - 1)
By taking LCM u get
(2x-2+3x+3)/(x^2 - 1) = 5(x^2 -1) || bcoz (a+b)(a-b) = (a^2 - b^2)
therefore 5x+1 = 5
it's just simple fractions
note that the product of the two denominators on the left side of the equation is equal to the denominator on the right side
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Verified answer
2/(x + 1) + 3/(x - 1) = 5/(x² - 1)
(2x - 2 + 3x + 3)/(x² - 1) = 5/(x² - 1)
5x + 1 = 5
5x = 4
x = 4/5
Answer: x = 4/5
Proof:
2/(4/5 + 1) + 3/(4/5 - 1) = 5/([4/5]² - 1)
2/(4/5 + 5/5) + 3/(4/5 - 5/5) = 5/(16/25 - 25/25)
2/(9/5) + 3/(- 1/5) = 5/(- 9/25)
2(5/9) + 3(- 5) = 5(- 25/9)
10/9 - 15 = - 125/9
10/9 - 135/9 = - 125/9
- 125/9 = - 125/9
2/(x+1)+3/(x-1)=5/(x^2-1)
now solving you will get
2(x-1)+3(x+1)/(x^2-1)=5/(x^2-1)
cancelling out we get
5x-4=0
x=4/5
2/(x+1) + 3/(x-1) = 5/(x^2 - 1)
By taking LCM u get
(2x-2+3x+3)/(x^2 - 1) = 5(x^2 -1) || bcoz (a+b)(a-b) = (a^2 - b^2)
therefore 5x+1 = 5
5x = 4
x = 4/5
it's just simple fractions
note that the product of the two denominators on the left side of the equation is equal to the denominator on the right side