How to determine the formula of hydrate CuSO4 • 5H2O?

Im writing a formal lab report and I need to explain how we ended up with x ( which was where the 5 is in the formula and our answer was 4.78) I can't remember how we got there and I need to explain it in the lab. Thanks.

Update:

the mass of empty evaporating dish was 40.892g mass of the hydrated compound was 2.994g mass of evaporating dish and CuSO4 anhydrous was 42.836g.

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