How to use Kepler’s third law, P2 = a3, to verify that the orbits of Kuiper belt objects with a = 47.8 AU are in a 2:1 resonance with Neptune?
Neptune is 30.06 AU from the Sun (one ref - another gives 30.07)
T^2 = R^3 so T^2 = (47.8/30.06)^3 = 4.02
So ratio of times is sqr(4) = 2
hence 2:1 resonance.
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Neptune is 30.06 AU from the Sun (one ref - another gives 30.07)
T^2 = R^3 so T^2 = (47.8/30.06)^3 = 4.02
So ratio of times is sqr(4) = 2
hence 2:1 resonance.