解題:-設—皮球,畫上正面五边形.
伸展四==左兩右兩,綫 作4相同正方形;
放棄中上正线 則分割成立.
ie:-36-16=20=5x4;
1* + 4x1 =1 + 4 =5.
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
解題:-設—皮球,畫上正面五边形.
伸展四==左兩右兩,綫 作4相同正方形;
放棄中上正线 則分割成立.
ie:-36-16=20=5x4;
1* + 4x1 =1 + 4 =5.