You push with a
force of 125 pounds to slide a 250–pound
crate up an inclined plane. The inclined plane is 12
feet long and the upper end is 5 feet
above the lower end.
The angle is arcsin (5/12)
The weight is 250 pounds, and the component parallel to the ramp is 500 sin θ
which is 500 (5/12) = 208 lb.
so the friction is 250–208 = 42 lb
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Verified answer
The angle is arcsin (5/12)
The weight is 250 pounds, and the component parallel to the ramp is 500 sin θ
which is 500 (5/12) = 208 lb.
so the friction is 250–208 = 42 lb