How many moles of H₂SO₄ are required to completely react with 7.20 mol of Al according to the balanced chemical reaction?
How many moles of H₂SO₄ are required to completely react with 7.20 mol of Al according to the balanced chemical reaction:
2Al (s) + 3 H₂SO₄ (aq) → Al₂(SO₄)₃ (aq) + 3H₂ (g)
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( 7.20 mol Al) x (3 mol H₂SO₄ / 2 mol Al) = 10.8 mol H₂SO₄