As I work this problem, I will round my final answer to three significant digits. The mass of one mole of zinc is 65.4 grams.

n = 23.5 ÷ 65.4

P = 588 ÷ 760

T = 17 + 273 = 290˚K

Let’s use these numbers in the Ideal gas law equation.

(588 ÷ 760) * V = (23.5 ÷ 65.4) * (22.4 ÷ 273) * 290

104,982,696 * V = 116,018,560

V = 116,018,560 ÷ 104,982,696

The volume is approximately 1.11 liter. I hope this is helpful for you.

Supposing the reaction to be something like:

Zn + 2 H{+} → Zn{2+} + H2

(23.5 g Zn) / (65.380 g Zn/mol) x (1 mol H2 / 1 mol Zn) = 0.35944 mol H2

V = nRT / P = (0.35944 mol) x (62.36367 L mmHg/K mol) x (17 + 273) K / (588 mmHg) = 11.1 L H2