How many grams of oxygen gas are produced when 2.43 x 10⁻⁴ g of KClO₃ are completely reacted according to the following chemical equation:?
How many grams of oxygen gas are produced when 2.43 x 10⁻⁴ g of KClO₃ are completely reacted according to the following chemical equation:
2KClO₃ (s) → 2KCl (s) + 3 O₂ (g)
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(2.43 × 10^-4 g KClO₃) / (122.5495 g KClO₃/mol) × (3 mol O₂ / 2 mol KClO₃) ×
(31.99886 g O₂/mol) = 9.52 × 10^-5 g