√200-√32 becomes 6√2
What are the steps and how does this happen?
1. √200-√32
2. ???
3. 6√2
What are the intermediate steps?
√200 - √32
√(100*2) - √(16*2)
10√2 - 4√2
6√2
sqrt(200) - sqrt(32)
= sqrt(100 * 2) - sqrt(16 * 2)
= 10sqrt(2) - 4sqrt(2)
= 6sqrt(2)
sqrt(200) = sqrt(10*2) = 10*sqrt(2)
sqrt(32) = sqrt(16*2) = sqrt(16)*sqrt(2) = 4*sqrt(2)
10*sqrt(2)-4*sqrt(2)= (10-4)*sqrt(2) = 6*sqrt(2)
root200 can be written root(2x100)=10root2
root32 can be written root (2x16) = 4root2
root200 - root32 = 10root2 - 4root2 = 6root2
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Verified answer
√200 - √32
√(100*2) - √(16*2)
10√2 - 4√2
6√2
sqrt(200) - sqrt(32)
= sqrt(100 * 2) - sqrt(16 * 2)
= 10sqrt(2) - 4sqrt(2)
= 6sqrt(2)
sqrt(200) = sqrt(10*2) = 10*sqrt(2)
sqrt(32) = sqrt(16*2) = sqrt(16)*sqrt(2) = 4*sqrt(2)
10*sqrt(2)-4*sqrt(2)= (10-4)*sqrt(2) = 6*sqrt(2)
root200 can be written root(2x100)=10root2
root32 can be written root (2x16) = 4root2
root200 - root32 = 10root2 - 4root2 = 6root2