How does √(2x KE)/M link/relate to this question, How does height affect the speed of trolley car at the bottom of the ramp.
I need a good explanation Thank You
You haven't said what the related question is, other than mentioning a trolley and ramp.
The formula you give is for velocity if you know kinetic energy, KE
KE = (1/2)mv^2
2KE/m = v^2
v = √(2KE/m)
Here's an example. If a trolley rolls downhill from rest (no friction) and the height change is h, what is the speed at the bottom?
Loss of gravitational potential energy = Gain in kinetic energy (because of conservation of energy)
mgh = KE
= √(2mgh/m)
=√(2gh)
Height affects gravitational PE. The gravitational PE is equal to the KE it gets at the bottom of the ramp.
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
You haven't said what the related question is, other than mentioning a trolley and ramp.
The formula you give is for velocity if you know kinetic energy, KE
KE = (1/2)mv^2
2KE/m = v^2
v = √(2KE/m)
Here's an example. If a trolley rolls downhill from rest (no friction) and the height change is h, what is the speed at the bottom?
Loss of gravitational potential energy = Gain in kinetic energy (because of conservation of energy)
mgh = KE
v = √(2KE/m)
= √(2mgh/m)
=√(2gh)
Height affects gravitational PE. The gravitational PE is equal to the KE it gets at the bottom of the ramp.