How do I solve sin Ø = 0.5?
I have been gone from math and plan on going in for help when i come back - but have homework I have to do when I'm gone and have absolutely no idea where to begin.
Other equations on the problems are
2. cos Ø = -.05
3. 4 tan Ø = 0
4. 3 sin^2 = 1
Update:4. 3 sin^2-4=0*
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sin(θ) = 0.5
θ = π/6 or θ = π - π/6 = 5π/6
θ = π/6 + 2kπ or θ = 5π/6 + 2kπ, where k is an integer number
2. cos(θ) = -0.5
θ = π/3 or θ = - π/3
θ = π/3 + 2kπ or θ = - π/3 + 2kπ, where k is an integer
3. 4 tan(θ) = 0
tan(θ) = 0
θ = 0 + kπ, where k is an integer
4. 3 sin²(θ) - 4 = 0
sin²(θ) = 4/3
sin(θ) = ± 2(√3)/3
Whereas -1 ≤ sin(θ) ≤ 1, these solutions above are not adequate.