Basic Triangle inequality is
|a+b|≤|a|+|b|
Now we are given that
|x+3|<½
so
|4(x+3)| < 4(½)
thus
|4x+12| < 2
Now let a = 4x+ 12 and b = 1
|4x+12 + 1||≤|2|+|1|
|4x+13||≤3
However, for this to be ≤ , at least for
the = part to be possible
|4x+12| would have to be equal to 2
since both would have to equal the same a
However we know
|4x+12|<12, no equals to line under <
|4x+13|< 3 with no equals to line and our
demonstration is now complete.
i too have the same problem , i have used many things but it doesnt work or jst for few days ,better is not think about it n dont touch it ; they will end themselves . but u can also use proactiv ,it shows better results
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
Basic Triangle inequality is
|a+b|≤|a|+|b|
Now we are given that
|x+3|<½
so
|4(x+3)| < 4(½)
thus
|4x+12| < 2
Now let a = 4x+ 12 and b = 1
so
|4x+12 + 1||≤|2|+|1|
so
|4x+13||≤3
However, for this to be ≤ , at least for
the = part to be possible
|4x+12| would have to be equal to 2
since both would have to equal the same a
However we know
|4x+12|<12, no equals to line under <
so
|4x+13|< 3 with no equals to line and our
demonstration is now complete.
i too have the same problem , i have used many things but it doesnt work or jst for few days ,better is not think about it n dont touch it ; they will end themselves . but u can also use proactiv ,it shows better results