how do i integrate ∫3cos^2 xsinx dx using u substitution?
Integration by substitution is explained with a link in the source.
∫ 3sinxcos²x dx
Let u = cosx,
du / dx = -sinx
du = -sinx dx
-du = sinx dx
-3 ∫ u² du
-u³ + C
Since u = cosx,
-cos³x + C
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Verified answer
Integration by substitution is explained with a link in the source.
∫ 3sinxcos²x dx
Let u = cosx,
du / dx = -sinx
du = -sinx dx
-du = sinx dx
-3 ∫ u² du
-u³ + C
Since u = cosx,
-cos³x + C