Verified answer

2a^2 + 1 + 3a

2a^2 + 3a + 1

2a^2 + 2a + a + 1

2a(a + 1) + 1(a + 1)

(2a + 1)(a + 1)

a*c ?

Rewrite 2a^2 + 3a + 1

Multiply 2 by 1 to get 2.

Find two numbers such that when you multiply them, you get 2 and when you add them you get 3. They are 2 and 1. Now replace 3a in the expression with 2a +1a and factor

2a^2 + 2a + 1a + 1

2a(a + 1) + 1(a + 1)

(2a + 1)(a + 1)

2a^2+3a+1=2a^2+2a+a+1=

2a(a+1)+1(a+1)=

(2a+1)(a+1)