Verified answer

y = sqrt(x-3), x ≥ 3 and y ≥ 0

Switch x and y, and square both sides,

x^2 = y - 3

f^-1(x) = y = x^2+3, y ≥ 3 and x ≥ 0

The inverse is a function.

y =√x-3

interchange x and y

x =√y-3

get the square of each side

x^2 = y - 3

express in y form

y = x^2 + 3

therefore f^ -1 (x) = x^2 +

the graph is symmetric to the line y = x

two functions, the inverse is a function if and only if there is no element of x is repeated for different element of y.... in graph, when the vertical line test touches the graph at one point only.... when there is no even exponent in y (in equation)

Inverse:

x = sqrt(y) - 3

x + 3 = sqrt(y)

y = (x+3)^2 <- stated as a function

You can graph It on any graphing calc