This looks like the formula for volume of a right circular cone - but I believe you have a typo in the original problem; it should read: V=1/3πr^2h (if there isn't a typo, my apologies).
To solve the problem, you need to get the h alone. For the problem at hand that is relatively easy since everything attached to the h is by multiplication - this means you only have to divide each side by those things you don't want to keep (which is everything but the h). Let's get started (I'll use mine, just in case) - so you want to divide both sides by 1/3πr^2:
→ V=1/3πr^2h
→ V/(1/3πr^2) = (1/3πr^2h)/(1/3πr^2)
To clean this up, you need to remember that when there is a fraction in the denominator of another fraction, the fraction in the denominator gets flipped and is multiplied:
→ (3/1)V/(πr^2) = (1/3πr^2h)/(1/3πr^2)
→ 3V/(πr^2) = h
Check your work with the original problem (again, my version):
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Hello,
This looks like the formula for volume of a right circular cone - but I believe you have a typo in the original problem; it should read: V=1/3πr^2h (if there isn't a typo, my apologies).
To solve the problem, you need to get the h alone. For the problem at hand that is relatively easy since everything attached to the h is by multiplication - this means you only have to divide each side by those things you don't want to keep (which is everything but the h). Let's get started (I'll use mine, just in case) - so you want to divide both sides by 1/3πr^2:
→ V=1/3πr^2h
→ V/(1/3πr^2) = (1/3πr^2h)/(1/3πr^2)
To clean this up, you need to remember that when there is a fraction in the denominator of another fraction, the fraction in the denominator gets flipped and is multiplied:
→ (3/1)V/(πr^2) = (1/3πr^2h)/(1/3πr^2)
→ 3V/(πr^2) = h
Check your work with the original problem (again, my version):
→ V=1/3πr^2h
→ V=1/3πr^2(3V/(πr^2))
→ V=V → the answer checks and you are done!
Thanks for interesting question!
Jeffrey
h = 3V/Ïr^2