Heat Transfer Problem : Air at 300°C flows over a flat plate of dimensions 0.50 m by 0.25 m. ................?
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Air at 300°C flows over a flat plate of dimensions 0.50 m by 0.25 m. If the convection heat transfer coefficient is 250 W/m² K, determine the heat transfer rate from the air to one side of the plate when the plate is maintained at 40°C.
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To answer this question, you simply have to understand the premise of a heat transfer coefficient. You are given the heat transfer coefficient, so someone else has done all the difficult work for you. Usually, that is the challenge, because you need to understand the conditions of the flow and how the geometry affects it.
To understand the heat transfer coefficient (htc, as I call it), simply look at the units. It is the heat transfer rate in Watts, per unit area in meters^2, per unit temperature differential, in units of Kelvin. Remember that a numerically equal temperature differential in Kelvin and Celsius are identical.
Thus, we can write an equation for heat transfer rate:
Q_dot = htc*deltaT*A
Q_dot = htc*(T_air - T_plate)*(L*W)
Data:
htc = 250 W/m^2-C
L = 0.5 m
W = 0.25 m
T_air = 300 C
T_plate = 40 C
Result:
Q_dot = 8125 Watts
T = 300 Degree C = 573 K...
Area of plate = 0.5 * 0.25 = 0.125 m^2...
Heat transfer coefficient = 250 W/m² K
Final temperature = 40 Degree = 313K...
Q = h * A * (T2 - T1)
where Q is the heat transfer...
Q = 250 * 0.125 * ( 573 - 313 ) = 8125 W...
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