Hail comes straight down at a mass rate of m/Δt = 0.030 kg/s and an initial velocity of v0 = -14 m/s and strikes the roof perpendicularly. Unlike rain, hail usually does not come to rest after striking a surface. Instead, the hailstones bounce off the roof of the car. Suppose that the hail bounces off the roof of the car with a velocity of +14 m/s. Ignoring the weight of the hailstones, calculate the force exerted by the hail on the roof.
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Verified answer
One is not really "ignoring" the weight of the hailstones;
it is implicit in the combination of their mass and the
downward velocity they acquired due to gravity...
However, the calculation desired by those posing the problem is:
F = dp/dt, where p is linear momentum, and it turns out to be
(0.030 kg/s) (14 m/s - (-14 m/s)) = 0.84 kg m/s^2 = 0.84 N