Given the reaction 2 C2H2(g) + 5 O2(g) → 4CO2(g) + 2H2O(g), how much oxygen gas is needed for the complete com?
Given the reaction 2 C2H2(g) + 5 O2(g) →
4CO2(g) + 2H2O(g), how much oxygen gas is needed for the complete combustion of 166 g of acetylene
(C2H2)? Answer in units of g.
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ok so first work out molar ratios of the equation so that's 2-5-4-2 (assuming it's balanced correctly) this means that for every 2 moles of ethyne (actylene) burnt 5 moles of O2 are needed. so firstly you work out how many moles of C2H2 you have (6.38 moles) now cause for every 2 moles of C2H2 5 moles of O2 are needed you then go 5/2*6.38 meaning 15.95 les of O2 are burnt. now multipy that by 32 (molar mass of oxygen) gives you total mass of oxygen needed which is 510.4 grams
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I got 510.78g.